Question

ABC is a right triangle. If AC = 12 and BC = 13, find AB.

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

There is a right triangle given, please refer the diagram I have attached.

Using Pythagorean theorem,

$AC^2+AB^2=BC^2$

Plugging the value of sides in theorem

$12^2 + AB^2 = 13^2$

$144+AB^2=169$

$AB^2 = 169-144$

$AB^2 = 25$

Taking square root on both sides

$AB = 5$  ..................   Answer

Hpe it will help :)

Answer 2

Since BC is the hypotenuse...

α = 12
c = 13

Hence..

13² = 12² + ß²
ß = √(13² - 12²)
= √(169 - 144)
= √25
= 5

Hence, AB = 5

I hope this helps!