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blondinia [14]
3 years ago
7

A number to be multiplied is called a

Mathematics
2 answers:
Elina [12.6K]3 years ago
7 0
Multiplicand is the answer
MatroZZZ [7]3 years ago
5 0

Answer:

a non linear function to the algrithm

Step-by-step explanation:

magth

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Can you pls help me with this plsss
Gelneren [198K]
Sure! So you need to make an addition problem, for example, 200+25; that equals 225, right? Now you need to subtract from 225. For example, 225-10= 215. Hope I helped!
8 0
3 years ago
Find the area of a triangle if the base is 8.2 m and the height is 4.6 m. (A=1/2bh)
Tcecarenko [31]

Answer:

18.86

Step-by-step explanation:

8.2 x 4.6 = 37.72

37.72/2 = 18.86

5 0
3 years ago
Read 2 more answers
Several years​ ago, 50​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1095, \pi = \frac{478}{1095} = 0.4365

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

5 0
3 years ago
I'll give brainliest!! please help me!! Given f(x)=10x+8 and g(x)=1x+4
Artyom0805 [142]
The answer should be 31
(10(3)+8)-(1(3)+4)
(30+8)-(3+4)
= 31
3 0
4 years ago
A manufacturer claims that its drug test will detect steroid use (that is, show positive for an athlete who uses steroids) 95% o
amid [387]

Answer:

The probability tree is;

                            0.95        (+)

                   (S)

          0.1              0.05        (-)

[  P  ]

          0.9             0.15          (+)                                                        

                  (S_{no})    

                             0.85         (-)        

Step-by-step explanation:

Given the data in the question;

10% of the rugby team members use steroids

so Probability of using steroid; P( use steroid ) = 10% = 0.10

Probability of not using steroid; P( no steroid use ) = 1 - 0.10 = 0.90

Since the test show positive for an athlete who uses steroids, 95% of the time.

Probability of using steroids and testing positive = 95% = 0.95

Probability of using steroids and testing Negative = 1 - 0.95 = 0.05

Also from the test, 15% of all steroid-free individuals also test positive.

so

Probability of not using steroids and testing positive = 15% = 0.15

Probability of not using steroids and testing negative = 1 - 0.15 = 0.85

To set up the probability tree, Let;

(S) represent steroid use

(S_{no}) represent no steroid use

(+) represent test positive

(-) represent test negative

so we have;

                            0.95        (+)

                   (S)

          0.1              0.05        (-)

[  P  ]

          0.9             0.15          (+)                                                        

                  (S_{no})    

                             0.85         (-)        

7 0
3 years ago
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