Dy/dx = dy/dt * dt/dx
xy = 4
y + x(dy/dx) = 0 by implicit differentiation.
x(dy/dx) = -y
dy/dx = -y/x
<span>dy/dx = dy/dt * dt/dx dy/dt = -2
</span>
<span>-y/x = -2 * dt/dx
</span>
y/(2x) = dt/dx
dt/dx = y/(2x)
dx/dt = 2x/y
When x = -3, xy = 4, y = 4/x = 4/-3 = -4/3
dx/dt = 2*-3/(-4/3) = -6 *-3/4 = 18/4 = 9/2 = 4.5
dx/dt = 4.5
Answer:
a) for all values of x that are in the domains of f and g.
b) for all values of x that are in the domains of f and g.
c) for all values of x that are in the domains of f and g with g(x)≠0
Step-by-step explanation:
a) By definition (f+g)(x)=f(x)+g(x). Then x must be in the domain of f and g.
b) By definition (fg)(x)=f(x)g(x). Then x must be in the domain of f and g.
c) By definition (f/g)(x)=f(x)/g(x). Then x must be in the domain of f and g and g(x) must be different of 0.
Answer:
x
19/6
Step-by-step explanation:
1. Multiply both sides by 6 (the LCM of 6,3)
5/2 + 3-x <= 2(x-2)
2. Simplify 5/2+3-x to 11/2-x
11/2 - x<=2 (x-2)
3. Expand.
11/2-x<= 2x-4
4. Add x to both sides.
11/2<= 2x-4+x
5. Simplify 2x-4+x to 3x-4.
11/2<=3x-4
6. Add 4 to both sides.
11/2+4<=3x
7. Simplify 11/2+4 to 19/2
19/2<=3x
8. Divide both sides by 3
19/2 /3 <=x
9. Simplify 19/2 /3 to 19/2*3
19/2*3<=x
10. Simplify 2*3 to 6
19/6<=x
11. Switch sides.
x>= 19/6
Hope this helps!
M can be any positive real number.
Explanation:
From f(x) = √(mx) ; if x is posive m has to be positive; if x is negative m has to be negative; if x is cero m can have any value, and the range will always be 0 or positve
From g(x) = m √x; x can only be 0 or positive and the range will have the sign of m.
Given we concluded that the range of f(x) can only be 0 or positive, then me can only be 0 or positive.
<span>-6x - 2 = 40
-6x = 42
x = -7
..................</span>
