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Airida [17]
4 years ago
13

What are the solution(s) to the quadratic equation 50 – x2 = 0?

Mathematics
2 answers:
Novay_Z [31]4 years ago
8 0

Answer:

Solution of the given Quadratic equation are +5√2 and -5√2.

 

Step-by-step explanation:

We are given Quadratic Equation,

50-x^2=0

To find: Solutions of the given quadratic equation.

Consider,

50-x^2=0

transpose x² to RHS,

50=x^2

Now transpose whole RHS to LHS and whole LHS to RHS,

x^2=50

Now, Apply square root both sides,

x=\pm\sqrt{50}

x=\pm\sqrt{2\times5\times5}

x=\pm5\sqrt{2}

Therefore, Solution of the given Quadratic equation are +5√2 and -5√2.

Alecsey [184]4 years ago
5 0
I hope this helps you



x^2=50


x= 5 square root of 2
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If the angles of a convex octagon are 2x+6,x+13,2x-1,2x+12,2x-17,3x-4,3x-10,4x. then the smallest angle is 21°.

Given The exterior angles of convex octagon are 2x+6,x+13,2x-1,2x+12,2x-17,3x-4,3x-10,4x.

and we have to find the value of smallest angle.

The sum of the  angles of a convex octagon is 360°

so to calculate the smallest angle we need to find out the value of x first and which is calculated by summing up all the exterior angles and put them equal to 360.

(2x+6)+(x+13)+(2x-1)+(2x+12)+(2x-17)+(3x-4)+(3x-10)+4x=360

2x+6+x+13+2x-1+2x+12+2x-17+3x-4+3x-10+4x=360

2x+x+2x+2x+2x+3x+3x+4x+6+13-1+12-17-4-10=360

19x-1=360

19x=360+1

19x=361

x=361/19

x=19

Putting the value of x in all the angles and we will find the following:

2x+6=2*19+6=44

x+13=19+13=32

2x-1=2*19-1=37

2x+12=2*19+12=50

2x-17=2*19-17=21

3x-4=3*19-4=51

3x-10=3*19-10=47

4x=4*19=76

Hence among all the exterior angles the smallest angle is 21°.

Learn more about angles at brainly.com/question/25716982

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