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AysviL [449]
4 years ago
6

Find the measure of each angle indicated

Mathematics
1 answer:
Alenkinab [10]4 years ago
3 0
The measure of the angle is 150 degrees.

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How would i solve this does anyone know?
KATRIN_1 [288]
You need to use pythagorean’s theorem. so a^2+b^2=c^2.

in this case it would be 6^2+8^2=c2

36+64=100

the square root of 100 is 10

x=10
7 0
2 years ago
Using rigid motion, which statement is true about the triangles? △ABC is congruent to △DEF . △ABC is congruent to △FDE . △ABC is
julia-pushkina [17]

Answer:

△ABC is congruent to △DEF

Step-by-step explanation:

△DEF is a reflection of △ABC across the y-axis. (Each x-coordinate is negated.)

_____

<em>Comment on presentation</em>

This would be much easier to answer if you would use a conventional representation of ordered pairs:

... (-1, -2) instead of "begin ordered pair negative 1 comma negative 2 end ordered pair"

5 0
4 years ago
Read 2 more answers
Please help ASAP!!!!!!!!!!!!!
SIZIF [17.4K]

Answer:good luck yo

Step-by-step explanation:2 times 5

8 0
3 years ago
What is the midpoint of the segment shown below? (-2,4) (6,-4)
tresset_1 [31]
<h2>solution :</h2>

let's assume the Coordinates be x and y

By using Section formula,

\boxed{ x =  (\dfrac{x_2 + x_1}{2} )}

  • x =   \dfrac{ - 2 + 6}{2}

  • x =  \dfrac{4}{2}

  • x = 2

____________________

\boxed {y =  (\dfrac{y_2 + y_1}{2} )}

  • \dfrac{ - 4 + 4}{2}

  • \dfrac{0}{4}

  • 0

____________________

\mathrm{Therefore \:\:the\:\: Coordinates\:\: of \:\:the\;\; mid-point\;\: of \;\;the\:\: given\:\: segment\:\; is}

\huge \boxed{(2,0)}

_____________________________

\mathrm{ \#TeeNForeveR} \: ☃

8 0
3 years ago
Can you guys help me on question 10?
Serjik [45]
Really.................you really can’t figure this out
3 0
3 years ago
Read 2 more answers
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