Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
it is D
Step-by-step explanation:
Answer:
d. not a real number
Step-by-step explanation:
it is not a real number because theres a negative under root
A-9 2/3 B-3 3/8 C-5 D-4 1/5
Answer:
<u>the frequency</u> is the number of times a particular value occurs in a given data.
