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aleksley [76]
3 years ago
9

How many solutions does the following equation have? 4x + 3x - 8 = 14 + 7x

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

There is no solution.

You might be interested in
If y varies directly as x, and y = 10 when x = 9, find y when x = 1/9
Vinvika [58]

Answer:

10/81

Step-by-step explanation:

let,

y=kx

y=10 when x=9

so,

10=k×9

or, k=10/9

when x=1/9

y=kx

or, y=(10/9)×(1/9)

or, y=10/81

5 0
3 years ago
Choose the system of equations that matches the following graph:
IrinaVladis [17]
The  correct option as per me is (b)
6 0
3 years ago
Solve | x + 6| - 7 = 8
Alex

Answer:

x = 9,-21

Step-by-step explanation:

Given:

\displaystyle \large{|x+6|-7=8}

Transport -7 to add 8:

\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}

Cancel absolute sign and add plus-minus to 15:

\displaystyle \large{x+6=\pm 15}

Transport 6 to subtract ±15:

\displaystyle \large{x=\pm 15-6}

Consider:

\displaystyle \large{x= 15-6} or \displaystyle \large{x = -15-6}

\displaystyle \large{x=9} or \displaystyle \large{x=-21}

Solution:

\displaystyle \large{x = 9} or \displaystyle \large{x=-21}

__________________________________________________________

Second Method

Given:

\displaystyle \large{|x+6|-7=8}

Transport -7 to add 8:

\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}

Absolute Function Property:

\displaystyle \large{|x-a| = \begin{cases} x-a \ \ (x \geq a) \\ -x+a \ \ (x < a) \end{cases}}

Consider both intervals:

When x ≥ a then:

\displaystyle \large{|x+6|=15}\\\displaystyle \large{x+6=15}

Transport 6 to subtract 15:

\displaystyle \large{x=15-6}\\\displaystyle \large{x=9}

When x < a then:

\displaystyle \large{|x+6|=15}\\\displaystyle \large{-(x+6)=15}\\\displaystyle \large{-x-6=15}

Transport -6 to add 15:

\displaystyle \large{-x=15+6}\\\displaystyle \large{-x=21}

Transport negative sign to 21:

\displaystyle \large{x=-21}

Solution:

\displaystyle \large{x=9} or \displaystyle \large{x=-21}

__________________________________________________________

Let me know if you have any questions regarding this question, my answer or explanation. Hope this answer and explanation helps you and good luck with your assignment!

3 0
2 years ago
Please help!! :) Thank you!
Klio2033 [76]

Let's complete the square

f(x) = x^2 + 6x + 8

y = x^2 + 6x + 8

y-8 = x^2 + 6x

y-8+9 = x^2+6x+9 .... see note below

y+1 = (x+3)^2

y = (x+3)^2-1

note: I added 9 to both sides due to taking half of the 6, and then squaring that result.

We'll restrict x such that x \ge -3 to ensure that this function is one-to-one.

Now we need to swap x and y, and solve for y to get the inverse

y = (x+3)^2 - 1

x = (y+3)^2 - 1

x+1 = (y+3)^2

(y+3)^2 = x+1

y+3 = sqrt(x+1)

y = sqrt(x+1)-3

g(x) = sqrt(x+1)-3     is the inverse

The graph is shown below. The original function is in red. The inverse is in blue. The inverse is the result of reflecting the red curve over the dashed line y = x. So this explains why x and y swap places. Consequently, the domain and range also swap as well.

4 0
3 years ago
How many solutions does the following absolute value equation have? |x+3|=4
bekas [8.4K]
It has two solutions.
The first solution is x = -7
The second solution is x = 1

Hope this helps!
3 0
4 years ago
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