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2 years ago

Can someone help mee?

Mathematics

2 answers:

Gnoma [55]2 years ago

7 0

Answer: 1000

Step-by-step explanation:

The Sun: 10×10=100

KW Sagittaril: 10×10×10×10×10= 100,000

100,000/100 = 1000

Vesna [10]2 years ago

3 0

Answer:

i think 1000

Step-by-step explanation:

if 10 to the 5th power is 100000 and 10 to the 2nd power is 100 and you divide them the answer is 1000

You might be interested in

Choose one of the factors of x^3 + 343.

Debora [2.8K]

First, note that $343=7^3.$ Then use the formula for the sum of perfect cubes:

$a^3+b^3=(a+b)(a^2-ab+b^2).$

Therefore,

$x^3 + 343=x^3+7^3=(x+7)(x^2-7x+49).$

The quadratic trinomial $x^2-7x+49$ couldn't be factored anymore, so the expression $x^3 + 343$ has two factors $x+7$ and $x^2-7x+49.$

Answer: correct choice is A.

3 0

2 years ago

Please help me with these problems

S_A_V [24]

Answer:

1.a=2

2. C x=2 and x=-3

Step-by-step explanation:

The standard form for the quadratic function is

ax^2 +bx+c

so we need to rewrite the function to be in this form

2x^2 -10 = 7x

Subtract 7x from each side

2x^2 -7x-10 = 7x-7x

2x^2 -7x-10 = 0

a =2, b= -7 c=-10

2. The quadratic formula is

-b ± sqrt(b^2 -4ac)

----------------------------

2x^2 + 2x=12

Lest get the equation in proper form

2x^2 + 2x-12 = 12-12

2x^2 +2x-12 =0

a=2 b=2 c=-12

Lets substitute what we know

-2 ± sqrt(2^2 -4(2)(-12))

----------------------------

2(2)

-2 ± sqrt(4+96)

----------------------------

2(2)

-2 ± sqrt(100)

----------------------------

-2 ± 10

----------------------------

-2 + 10 -2-10

----------- and --------------

4 4

8/4 and -12/4

2 and -3

8 0

2 years ago

A car is traveling at a rate of 44 feet per second. What is the cats rate in miles per hour? How many miles will the car travel

Citrus2011 [14]

It takes 3600 seconds for one hour. It takes 14400 seconds for four hours.

Hope I helped!

6 0

3 years ago

Y<3x+4 in graph help me please!!!!

Zinaida [17]

Graph the boundary line of y = 3x + 4 first. This is pretty easy. I'll give the steps below.
1. plot the y intercept: we see from the equation, the y intercept is 4 or specifically the point (0,4).... plot this as your first point.
2. Use the slope to get another point or couple of points. We can see from the equation that the slope is 3(the coefficient of 'x') and can be represented as a fraction $\frac{3}{1}$ This fraction implies that you would move up three units of space and to the right 1 unit of space from the y intercept to get to your next point.
3. Draw a broken or dashed line through these two points due to the type of inequality symbol you have in the original problem(a less than symbol). This means the points that lie on this line will not actually by solutions.
4. Now that you have the boundary line sketched, all the points falling below the boundary line will be the solutions to the inequality <span>Y<3x+4 So shade that region of your graph.
5. To prove this, you can test the point (0,0) as follows: 0</span><span><3(0)+4
or, 0</span><4 which is a true statement, meaning the point (0,0) is a solution as well as all other points on that side of the boundary line.

Good luck ,, and I hope this helped.

7 0

3 years ago

I need help with this problem from the calculus portion on my ACT prep guide

LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r$

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

$\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}$

Then the limit is:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert$

We can simplify the expressions inside the absolute value:

$\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}$

Since none of the terms inside the absolute value can be negative we can write this with out it:

$\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}$

Now let's re-writte n/(n+1):

$\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}$

Then the limit we have to find is:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}$

Note that the limit of 1/n when n tends to infinite is 0 so we get:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4$

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

8 0

9 months ago