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Vikki [24]
3 years ago
11

Taylie wishes to advertise her business so she gives packs of 10 red flyers to each restaurant owner and sets of 8 blue flyers t

o each clothing store owner. At the end of the day, Taylie realizes that she gave out the same number of red and blue flyers. What is the minimum number of flyers of each color she distributed? How many packs of each did she hand out?
USE RACE!!!!!
Mathematics
1 answer:
frutty [35]3 years ago
6 0
If it’s adding it’s 18 it’s if’s division it’s 1.25 if it’s times it’s 80 if its taking away it’s 2
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Jaden says that two triangles are congruent if their interior angles are congruent. Is Jaden correct, and why?
Bogdan [553]

Answer:

No

Step-by-step explanation:

No. Congruent triangles should also have corresponding congruent side lengths.

5 0
2 years ago
Help me from 3 through 8
skad [1K]

Answer:

3)x=−9  and x=4

4)x=−12  and x=−5

5)x=8  and x=14

6)x=−7  and x=3

7)x=-1 2/3 and x = 1/4

8)x=2/5

Step-by-step explanation:

Hope this helps

7 0
3 years ago
Simplify the above question​
ankoles [38]

Answer:

0.75417552

reduced equals 0.75

Step-by-step explanation:

log(55/2)

log(81)

Decimal Form: 0.7541755

this answer is the anser if you are dividing log 10 and 27 1/3 by log 10 81

6 0
3 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
Suppose total benefits and total costs are given by b(y) = 100y − 8y2 and c(y) = 10y2. what is the maximum level of net benefits
olga nikolaevna [1]
Whenever you face the problem that deals with maxima or minima you should keep in mind that minima/maxima of a function is always a point where it's derivative is equal to zero.
To solve your problem we first need to find an equation of net benefits. Net benefits are expressed as a difference between total benefits and total cost. We can denote this function with B(y).

B(y)=b-c
B(y)=100y-18y²

Now that we have a net benefits function we need find it's derivate with respect to y.

\frac{dB(y)}{dy} =100-36y

Now we must find at which point this function is equal to zero.

0=100-36y
36y=100
y=2.8

Now that we know at which point our function reaches maxima we just plug that number back into our equation for net benefits and we get our answer.

B(2.8)=100(2.8)-18(2.8)²=138.88≈139.

One thing that always helps is to have your function graphed. It will give you a good insight into how your function behaves and allow you to identify minima/maxima points.


3 0
2 years ago
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