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2 years ago

Given the following matrices, find 3A - 2B. (Hint: find 3A and 2B first and then subtract.)

1 answer:

3 0

$A= \left[\begin{array}{cc}1&3\\5&2\end{array}\right] 
\\
\\3A=\left[\begin{array}{cc}3&9\\15&6\end{array}\right] 
\\
\\B= \left[\begin{array}{cc}4&9\\0&3\end{array}\right] 
\\
\\2B= \left[\begin{array}{cc}8&18\\0&6\end{array}\right] 
\\
\\3A-2B=\left[\begin{array}{cc}3&9\\15&6\end{array}\right]- \left[\begin{array}{cc}8&18\\0&6\end{array}\right]=\left[\begin{array}{cc}3-8&9-18\\15-0&6-6\end{array}\right]=
\\
\\=\left[\begin{array}{cc}-5&-9\\15&0\end{array}\right]$

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Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

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Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

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The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

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Let's rewrite that radical into exponential form:

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If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

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On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

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2 years ago

an ice cream shop manager lowered the price for a single scoop of ice cream from 2.50 to 2.00 what is the precent of decrease in

igomit [66]

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1 year ago

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Nat2105 [25]

Answer:

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Step-by-step explanation:

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Everything changed should be 16/24-9/24

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2 years ago

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3 years ago

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