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2 years ago

14

Natasha and her two dogs were walking on a perfectly straight road when her two dogs ran away from her in opposite directions. H

er beagle is now 25/4 meters directly to her right, and her labrador is 51/20 meters directly to her left.
The answer is B.

2 answers:

AlekseyPX2 years ago

5 0

The answer to this question is B

neonofarm [45]2 years ago

3 0

Answer is B.

Hope it helps.

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One canned juice drink is 15% orange juice another is 10% orange juice how many liters of each should be mixed together in order

vfiekz [6]

$\bf \begin{array}{lccclll}
&quantity(L)&concentration&
\begin{array}{llll}
concentrated\\
quantity
\end{array}\\
&-----&-------&-------\\
\textit{15\% juice}&x&0.15&0.15x\\
\textit{10\% juice}&y&0.10&0.10y\\
-----&-----&-----&-----\\
mixture&5&0.14&(5)(0.14)
\end{array}$

whatever the amounts of "x" and "y" are, they must add up to 5Liters
thus x + y = 5

and whatever the concentrated quantity is in each, they must add up to (5)(0.14)

notice, that we use the decimal notation for the amount of juice concentration, that is, 15% is just 15/100 or 0.15, and 14% is just 14/100 or 0.14 and so on, recall that "whatever% of something" is just (whatever/100)*something

thus $\bf \begin{cases}
x+y=5\implies \boxed{y}=5-x\\\\
0.15x+0.10y=(5)(0.14)\\
----------\\
0.15x+0.10\left(\boxed{5-x} \right)=(5)(0.14)
\end{cases}$

solve for "x", to see how much of the 15% juice will be needed

what about "y"? well, y = 5 - x

7 0

2 years ago

What is the value of x?

qaws [65]

Answer:

5

Step-by-step explanation:

6x+12 = 9x-3

3x = 15

x= 5

3 0

2 years ago

How are the values of -4^3 and 4^-3 alike and how do they differ?

BartSMP [9]

Answer:

(-4)³ = -64

(4)⁻³ = 1/64

Step-by-step explanation:

$( - 4) {}^{3} = ( - 4) \times ( - 4) \times ( - 4) = - 64 \\$

${4}^{ - 3} = (\frac{1}{4} ) {}^{3} \\$

$({ \frac{1}{4} )}^{3} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64} \\$

4 0

1 year ago

I really need help with these two above.

Strike441 [17]

6) y=-1/3x+5
7) y= x+5

8 0

2 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago