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3 years ago

if Mr Hughes had 2355 M of volleyball netting how many Nets can he make if each Court requires 9 meters of netting

Mathematics

2 answers:

Ymorist [56]3 years ago

7 0

The answer is 261 courts

lubasha [3.4K]3 years ago

4 0

Answer: 261 courts

Step-by-step explanation:

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State the domain of the relation.

gogolik [260]

Answer:

The Domain of the relationship is the set: {-3, -2, -1, 0, 1, 2} (Answer B)

Step-by-step explanation:

Let's recall that the Domain of a relationship is the set of values in the starting set for which there is a correspondent value in the final set.

In this case, we have a set of numbers on the x axis, which are connected with values in the y axis as indicated by the plotting of the points on the (x,y) plane.

The Domain will consist of all those x-values for which we see in the given plot connected to a corresponding y-value.

So, we see that:

the x-value -3 is connected to the y-value -4

the x-value -2 is connected to the y-value -3

the x-value -1 is connected to the y-value -1

the x-value 0 is connected to the y-value 0

the x-value 1 is connected to the y-value 3

and the x-value 2 is connected to two y-values: 4 and 5

Therefore all those x-values are part of the Domain of this relationship. That is, the set: {-3, -2, -1, 0, 1, 2}

7 0

3 years ago

In the Sahara fester one day it was 136 F degrees in the Goni desert a temperature of 50 degrees f Was recorded what is the diff

allochka39001 [22]

86 degrees Fahrenheit

3 0

3 years ago

Anybody have an answer to this ??

kondaur [170]

Answer:

Step-by-step explanation:

7 0

2 years ago

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

2 years ago

A square fits exactly inside a circle with each of its vertices being on the circumference of the circle.

swat32

Answer:

The side of the square is 5.971 cm

Step-by-step explanation:

If the square fits the circle exactly, then its diagonal is equal to the diameter of the circle. Since the side of the square has a length of $x$ cm, then it's diagonal have the length of $x\sqrt2$ cm. Using the circle's area we can find the diagonal of the square, as shown below:

$area = \pi*r^2\\56 = pi*r^2\\r^2 = \frac{56}{\pi}\\r = \sqrt{\frac{56}{\pi}}\\r = 4.222$

Since the diameter of the circle is the same as the diagonal of the square, then:

$x\sqrt{2} = 2*r \\x = \frac{2*r}{\sqrt{2}}\\x = \frac{2*4.222}{\sqrt{2}}\\x = 5.971$

The side of the square is 5.971 cm

8 0

3 years ago

Read 2 more answers

if Mr Hughes had 2355 M of volleyball netting how many Nets can he make if each Court requires 9 meters of netting ​

if Mr Hughes had 2355 M of volleyball netting how many Nets can he make if each Court requires 9 meters of netting