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Answer:
a. p1(x) = 2 - x
b. p2(x) = x² - 3*x + 3
c. p1(0.97) = 1.03; p2(0.97) = 1.0309
Step-by-step explanation:
f(x) = 1/x
f'(x) = -1/x²
f''(x) = 2/x³
a = 1
a. The linear approximating polynomial is:
p1(x) = f(a) + f'(a)*(x - a)
p1(x) = 1/1 + -1/1² * (x - 1)
p1(x) = 1 - x + 1
p1(x) = 2 - x
b. The quadratic approximating polynomial is:
p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²
p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²
p2(x) = 2 - x + (x - 1)²
p2(x) = 2 - x + x² - 2*x + 1
p2(x) = x² - 3*x + 3
c. approximate 1/0.97 using p1(x)
p1(0.97) = 2 - 0.97 = 1.03
approximate 1/0.97 using p2(x)
p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309
Answer: The slope is -2/5 and the y-intercept is -1/3
The answer is c 25 minutes btw hope you have a wonderful day