Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
B
Step-by-step explanation:
247 divided by 15 equals 16 and a whole bunch of nunbers
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3(4x+3) = 12x + 9
A= 3(4x+1)
B= 9 + 12x
C= 7x + 6
D= 12x + 9
E= 12x + 9
Answer: D, E
Hope This Helps✨
Step-by-step explanation:
radius of sphere, rs
radius of cylinder, rc
height of cylinder, h
given: h = rs = rc =r..eq1
volume of cylinder, vc = 27pi ft...eq2
volume of cylinder, vc = pi × rc^2 × h...eq3
volume of sphere, vs = 4/3(pi×rs^3)...eq4
subst for h & rs from eqn 1 in eqn 3...
vc = pi x r^2 x r= pi x r^3...eqn 5
subst for vc from eqn 2 in eqn 5...
=> 27 pi ft = pi x r^3
=> 27 = r^3
=> r = 3ft...eqn 6
subst for rs from eqn 1 in eqn 4
vs = 4/3 (pi x r^3)...eqn7
subst for pi x r^3 from eqn 5 in eqn 7
vs = 4/3 vc = 4/3 (27pi ft) = 36 pi ft
