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3 years ago

4x2-6 If x = 3 then has a value of what? X

1 answer:

3 0

I did not understand quite well, but I am assuming two possibilities, I hope it will be helpful.
If you meant what is the result 4x^2-6 if x equals to 3:
4(3)^2-6
12^2-6
144-6
=138

If you meant 4x(2)-6
4(3)(2)-6
12(2)-6
24-6
=18

Hope I could help!

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What is the value of x?

viktelen [127]

Answer:

x = 113

Step-by-step explanation:

The sum of the angles of a triangle are 180 degrees

37+54+ x-24 = 180

Combine like terms

67+x = 180

Subtract 67 from each side

67-67+x = 180-67

x =113

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3 years ago

Robin surveyed 5 students from the choirs of 4 different schools. He asked them how many hours they practice singing each day. S

Fittoniya [83]

Answer:

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3 years ago

Is 5.75 a terminating decimal or repeating decimal?

yawa3891 [41]

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3 years ago

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago

Find x, y, z, so that 41, 46, x, y, z has a mean of 50 and a mode of 45

nevsk [136]

Answer:

Step-by-step explanation:

as mode is 45 ,two of three is 45

i assume x =y=45

now (41+46+45+45+z)/5=50

177+z=50×5=250

z=250-177=73

so x=45

y=45

z=73

5 0

3 years ago

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