3 years ago

Are the expressions bh/2 and (1/2)bh equivalent expressions?

1 answer:

4 0

Bh/2 = (1/2)bh, so <span>bh/2 and (1/2)bh equivalent expressions</span>

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Burka [1]

Answer: $f'(1)=\dfrac{4}{2y+1}$

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given: 0 = 2x² - xy - y²

Derivative: 0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

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$\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}$

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3 years ago