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dolphi86 [110]
3 years ago
8

Are the expressions bh/2 and (1/2)bh equivalent expressions?

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0
Bh/2 = (1/2)bh, so <span>bh/2 and (1/2)bh equivalent expressions</span>
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Twice a number plus three times a second number is twenty two. Three times the first number plus four times the second is thirty
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The Hyperbolic Sine (sinh(x)) and Hyperbolic Cosine (cosh(x)) functions are defined as such: sin h(x) = e^x - e^-x/2 cosh(x) = e
labwork [276]

Answer:

y-incercepts:

sinh(x):0, cosh(x)=1

Limits:

positive infinity: sinh(x): infinity, cosh(x): infinity

negative infinity: sinh(x): - infinity, cosh(x): infinity

Step-by-step explanation:

We are given that

\sinh(x)=\frac{e^{x}-e^{-x}}{2}

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\cosh(0) = \frac{1+1}{2}=1

For the end behavior, recall the following:

\lim_{x\to \infty}e^{x} = \infty, \lim_{x\to \infty}e^{-x} = 0

\lim_{x\to -\infty}e^{x} = 0, \lim_{x\to -\infty}e^{-x} = \infty

Using the properties of limits, we have that

\lim_{x\to \infty} \sinh(x) =\frac{1}{2}(\lim_{x\to \infty}e^{x}-\lim_{x\to \infty}e^{-x})=(\infty -0) = \infty

\lim_{x\to \infty} \cosh(x) =\frac{1}{2}(\lim_{x\to \infty}e^{x}+\lim_{x\to \infty}e^{-x}) =(\infty -0)= \infty

\lim_{x\to -\infty} \sinh(x) =\frac{1}{2}(\lim_{x\to -\infty}e^{x}-\lim_{x\to -\infty}e^{-x}) = (0-\infty)=-\infty

\lim_{x\to -\infty} \cosh(x) =\frac{1}{2}(\lim_{x\to -\infty}e^{x}+\lim_{x\to -\infty}e^{-x}) =(0+\infty)= \infty

8 0
3 years ago
Michael's father bought him a 16 foot board to cut into shelves for his bedroom. Michael plans to cut the board into 11 equal pi
andrew-mc [135]
This may not be correct sorry , 16÷11 = 1.454545454545454545454545
6 0
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Are the roots equal or unequal ?<br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20-%206x%20%2B%209%20%3D%200" id="
vesna_86 [32]
This can be factored as (x-3)^2, so they are equal
3 0
2 years ago
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