Are the expressions bh/2 and (1/2)bh equivalent expressions?
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Given:
The base of 40-foot ladder is 8 feet from the wall.
To find:
How high is the ladder on the wall (round to the nearest foot).
Solution:
Ladder makes a right angle triangle with wall and ground.
We have,
Length of ladder (hypotenuse)= 40 foot
Base = 8 foot
We need to find the perpendicular to get the height of the ladder on the wall.
Let h be the height of the ladder on the wall.
According to the Pythagoras theorem,
Taking square root on both sides.
Height cannot be negative. Round to the nearest foot.
Therefore, the height of the ladder on the wall is 39 foot.
The bases are both 2, so we would subtract the exponents. This is because the rule is
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
(fourth root of 2)
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as
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