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dolphi86 [110]
2 years ago
8

Are the expressions bh/2 and (1/2)bh equivalent expressions?

Mathematics
1 answer:
andreev551 [17]2 years ago
4 0
Bh/2 = (1/2)bh, so <span>bh/2 and (1/2)bh equivalent expressions</span>
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Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
Hello can someone send me some documment for geometry where are the signs explained(Like )
Ket [755]

Answer:

https://revisionmaths.com/gcse-maths-revision/shape-and-space/vectors

i find this helpful- hope u do too (can u mark my answer as brainliest?)

3 0
3 years ago
Will mark brainliest<br> help?
Komok [63]

Answer:

It would go to quadrent 3

Step-by-step explanation:

4 0
2 years ago
What's 4+8*2(1+3)=??
Assoli18 [71]

Answer:

Step-by-step explanation:first:4+8 then 12*2 after:24+4

7 0
3 years ago
Is a location that has no size, represented by a small dot.
monitta
You need to tell us more information
6 0
3 years ago
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