All categories

2 years ago

Homework, 12 points for whoever answers.

Mathematics

2 answers:

adell [148]2 years ago

5 0

The answer to number 1 = 40

weqwewe [10]2 years ago

5 0

Question 1 answer: A:40

You can get this by adding 16 to 24 to figure out what number is the best solution, and by doing this you get 40. If you want to check your work you can always do 40-16 or 40-24 to make sure it checks out.

Question 2 answer: D:1875

You can get this by multiplying 75 by 25 to get your answer. This is probably the easiest way to get an answer.

Side Note: If you have any other questions about it feel free to ask me

You might be interested in

6. 150 is 75% of what number?

lora16 [44]

Answer: 8.2

Step-by-step explanation: So the way i do it is first i see that 6.15 is 75% of a number, and i know that 75% is 3/4. so i start by divided 6.15 by 3, and getting 2.05. i then times it by 4, making it 4/4. Therefore, getting 8.2

4 0

3 years ago

Read 2 more answers

NEED HELP ASAP

Anika [276]

Answer:

Y=4x+9

Step-by-step explanation:

Use rise over run to find 2 points for the slope. B is as simple as looking where the line passes y.

6 0

3 years ago

Read 2 more answers

Solve this equation 1/3t - 8 = -6

VARVARA [1.3K]

Answer:

t=6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is a perfect square 6, 10, 12, 14

vaieri [72.5K]

Answer:

None of the numbers are Perfect Square.

Step-by-step explanation:

6, 10, 12, and 14 are not <u>Perfect Square</u>, because each number are multiplied by two different numbers:

$6 = 3 \times 2$

$10 = 5\times 2$

$12 = 6\times 2$

$14 = 7 \times 2$

6 0

3 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0

3 years ago