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romanna [79]
2 years ago
13

Homework, 12 points for whoever answers.

Mathematics
2 answers:
adell [148]2 years ago
5 0
The answer to number 1 = 40
weqwewe [10]2 years ago
5 0

Question 1 answer: A:40

You can get this by adding 16 to 24 to figure out what number is the best solution, and by doing this you get 40. If you want to check your work you can always do 40-16 or 40-24 to make sure it checks out.

Question 2 answer: D:1875

You can get this by multiplying 75 by 25 to get your answer. This is probably the easiest way to get an answer.

Side Note: If you have any other questions about it feel free to ask me

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6 0
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∫(cosx) / (sin²x) dx
kirza4 [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822772

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\&#10;=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}


Make the following substitution:

\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}


and then, the integral (i) becomes

=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\&#10;=\mathsf{\displaystyle\int\! u^{-2}\,du}


Integrate it by applying the power rule:

\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\&#10;\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\&#10;\mathsf{=-\,\dfrac{1}{u}+C}


Now, substitute back for u = sin x, so the result is given in terms of x:

\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\&#10;\mathsf{=-\,csc\,x+C}


\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0
3 years ago
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