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3 years ago

-7+x÷14=-1 help I need a lot of help

Mathematics

2 answers:

nikdorinn [45]3 years ago

8 0

I think that x = 6 not sure

Anna71 [15]3 years ago

7 0

I hope this helps you

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Number 15-17<br> Please help!

Brrunno [24]

17dawdadawdadadawdad

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2 years ago

The temperature during the day in Miami was 92 degrees fahrenheit. During the night, the temperature fell 4 degrees fahrenheit.

BigorU [14]

You need to take away 4 degrees from 92.
"Take away" means subtraction.
92 - 4
The answer is option C.

4 0

2 years ago

Read 2 more answers

Solve the equation: 5/6 = 1/3 + D

Sauron [17]

Answer: $\frac{1}{2}$

Explanation:
$\frac{5}{6} = \frac{1}{3} + D$
$\frac{5}{6} - \frac{1}{3} = \frac{1}{3} - \frac{1}{3} + D$
$\frac{5}{6} - \frac{1}{3} = D$
$\frac{5}{6} - 2(\frac{1}{3}) = D$
$\frac{5}{6} - \frac{2}{6} = D$
$\frac{3}{6} = D$ = $\frac{1}{2}$

8 0

3 years ago

PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS

Reil [10]

Given

$x+1 = \sqrt{7x+15}$

We have to set the restraint

$x+1\geq 0 \iff x \geq -1$

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

$(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0$

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

$x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}$

So, we have to impose

$x-7\geq 0 \iff x \geq 7$

Squaring both sides, we have

$(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0$

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0

3 years ago

Evaluate : f(x) = x^2 - 2x + 1 , x = 3

den301095 [7]

Answer:

Step-by-step explanation:

3^2=9

-2 times 3 = -6

9-6+1=4

8 0

2 years ago