It's a quadratic equation in disguise. If you let , then
, and we can rewrite the equation as
Solve for however you like; we get
and
.
But we want to solve for , so we have
The rectangle shown has length AC = 32, width
1 answer:
Answer:
A. 320
Step-by-step explanation:
See attachment for the figure
in order to determine Area of quadrilateral ABDF, we'll use the formula i.e
Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)
whereas, area of AECD = (AC × AE)
Area of ΔBCD = 1/2 (BC x CD)
Area of ΔDEF =1/2 ( EF x ED)
Substituting in eq(1)
eq(1)=>
Area of quadrilateral ABDF = (AC × AE) - 1/2 (BC x CD)- 1/2 ( EF x ED)
=(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)
= 640 - 160 - 160
= 640 - 320
= 320 square unit
Therefore, the area of quadrilateral ABDF is 320 square unit
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