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zavuch27 [327]
3 years ago
10

What is the rate of exchange ? i dont understand what its asking

Mathematics
1 answer:
kirill115 [55]3 years ago
8 0
Simple
like when you buy something at the store. the person is selling products to you
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How many minutes are there in three quarters of an hour
Ivahew [28]
45 minutes.

3      x
---   ----
4     60

you multiply 60 and 3.
you get 180, then you divide by 4 and get 45 minutes.
8 0
3 years ago
Read 2 more answers
Write an equation of the line that passes through (−3,7) and is perpendicular to the line y=−2x−5.
Murljashka [212]

Answer:

Step-by-step explanation:

an equation is : Use the point-slope formula.

y - y_1 = m(x - x_1)    ;  m : the slope   when : x_1 = -3   and  y_1  = 7

- 2 ×m = - 1  because this line is perpendicular to the line y= -2x-5 when the slope is  -2

so : m= 1/2

an equation is : y - 7 =(1/2)(x+3)  

7 0
3 years ago
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Which expression is a factor of 3xy + 2x – 18y – 12?
aleksandr82 [10.1K]

x+6 is the right one


4 0
3 years ago
What is the value of x?
N76 [4]

Answer:

x=5

Step-by-step explanation:

\frac{x}{30}=\frac{4}{24}

\frac{x}{30}=\frac{1}{6}

x=\frac{1\times30}{6}

x=\frac{30}{6}

x=5

6 0
3 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
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