Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Substituting -3 for x, we have: (-3)^2-3*-3-7. This simplifies to 9+9-7, or 11.
Answer:
x
^2/
6
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Answer:
(2x +3) (4x +y)
Step-by-step explanation:
refer the image
The answer should be acute and scalene. Sorry if I’m wrong though
