Answer:
The area of APC is 70m². The area of triangle PMC is 35m².
Step-by-step explanation:
Let the area of triangle ABC be x.
It is given that AM is median, it means AM divides the area of triangle in two equal parts.
.....(1)
The point P is the midpoint of AB, therefore the area of APC and BPC are equal.
......(2)
The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.
.....(3)
The area of triangle APM is 35m².
Therefore the area of triangle ABC is 140m².
Using equation (2).
Therefore the area of triangle APC is 70m².
Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².
Therefore the area of triangle PMC is 35m².
To convert 180 degrees to its equivalent radian measure, multiply it with π/180.
180 (π/180)
The result is π radians.
This is also how the other angles in degrees are converted to radians. Simply multiply with π/180 and express the result in terms of pi.<span />
Answer:
$3.04
Step-by-step explanation:
$38 x .08 =3.04
Answer:
x = 136/11
, y = 68/11
Step-by-step explanation:
Solve the following system:
{6 x - y = 68
2 y = x
Hint: | Choose an equation and a variable to solve for.
In the second equation, look to solve for x:
{6 x - y = 68
2 y = x
Hint: | Reverse the equality in 2 y = x in order to isolate x to the left hand side.
2 y = x is equivalent to x = 2 y:
{6 x - y = 68
x = 2 y
Hint: | Perform a substitution.
Substitute x = 2 y into the first equation:
{11 y = 68
x = 2 y
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for y:
{11 y = 68
x = 2 y
Hint: | Solve for y.
Divide both sides by 11:
{y = 68/11
x = 2 y
Hint: | Perform a back substitution.
Substitute y = 68/11 into the second equation:
{y = 68/11
x = 136/11
Hint: | Sort results.
Collect results in alphabetical order:
Answer: {x = 136/11
, y = 68/11
