For what value of x is the value of f(x)=4x-2 equal to 18

Mathematics

2 answers:

tamaranim1 [39]3 years ago

7 0

F(5) = 4*5-2
f(5)= 20-2
f(5) = 18 the value of x is equal to 5 to make the function equal to 18.

mina [271]3 years ago

5 0

F(x) = 4(5) - 2 → f(x) = 20 - 2 → f(x) = 18

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PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

7 0

3 years ago

Please help!! I need to go to the next question!

tino4ka555 [31]

Given:

The inequality is:

$3t+1\leq 5$

To find:

The graph of the given inequality.

Solution:

We have,

$3t+1\leq 5$

Subtract both sides by 1.

$3t\leq 5-1$

$3t\leq 4$

Divide both sides by 3.

$t\leq \dfrac{4}{3}$

The value of t is less than or equal to $\dfrac{4}{3}$ .

Since $t\leq \dfrac{4}{3}$ , it means $\dfrac{4}{3}$ is included in the solution, therefore there is a closed circle at $t=\dfrac{4}{3}$ and an arrow approaches to left from $t=\dfrac{4}{3}$ .