Hi
f(x) = g(x) if -x²+3x-2 - ( -x+1) = 0
-x² +3x-2 +x-1 = 0
-x² +4x -3 = 0
To solve, tou have to use the general method of resolution of a quadratic fonction.
To determine if it's has a solution in R, let's calculate Δ
Δ = (4)² - 4 * (1) *(-3)
Δ = 16 +12
Δ= 28
as Δ≥ 0 so the function allow two solution within R
so S 1 = ( -4 +√28) / 2 S 2 = (-4 -√28 ) /2
S1 = ( -4 + 2√7) /2 S2 = (-4 - 2√7) /2
S1 = (2 (-2 +√7) /2 S2 2 (-2 -√7) /2
S1 = -2 +√7 S2 = -2 -√7
So the two function are equal twice. one for x = -2 +√7 and second x = -2-√7
Answer:
155
Step-by-step explanation:
The problem sounds complicated, but it's not. Let's analyse.
The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.
We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.
Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).
In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.
y= 11x + 12
=> In Tracy's case: y= 11*13 + 12= 155
So the number of retail stores there were in 2003 was 155
Hi, We know:
Sin(a + b) = 2.Sin(a).Sin(b)
Then,
= 2Sin(a).Cos(b)/Cos(a).Cos(b)
Canceling Cos(b)
= 2Sin(a)/Cos(a)
As Tan(a) = Sin(a)/Cos(a)
Then we will stay:
= 2Tan(a)
Or
= Tan(a) + Tan(a)
There is anything wrong on the alternatives
Answer:
you need to cut variable expenses first
Answer:
14
Step-by-step explanation:
18/2
9+5
<u>14</u>
