Show me your work please

What is the solution set of x2 + y2 = 26 and x − y = 6?

Viefleur [7K]

It works out that: y = 1 or 5 and therefore x = 5 or 1

4 0

3 years ago

In a survey, three out of four students said that courts show too much concern for criminals. Of seventy randomly selected stude

vladimir1956 [14]

Answer:

B. Yes, because P(X ≥ 68) ≤ .05

Step-by-step explanation:

The probability of a score X occuring is said to be unusually high if the probability of a score of X or larger is lower than 5%.

For each student, there are only two possible outcomes. Either they think that the court shows too much concern for criminals, or they do not think this. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

Three out of four students said that courts show too much concern for criminals. This means that $p = \frac{3}{4} = 0.75$

Would 68 be considered an unusually high number of students who feel that courts are partial to criminals?

We have to find $P(X \geq 68)$ .

$P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 68) = C_{70,68}.(0.75)^{68}.(0.25)^{2} < 0.000001$

$P(X = 69) = C_{70,69}.(0.75)^{69}.(0.25)^{1} < 0.000001$

$P(X = 70) = C_{70,70}.(0.75)^{70}.(0.25)^{0} < 0.000001$

So

$P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70) < 0.000003$

$P(X \geq 68)$ is lower than 0.05, so this is an unusually high number.

So the correct answer is:

B. Yes, because P(X ≥ 68) ≤ .05

5 0

3 years ago

Which of the following values are in the domain of the function graphed below? Check all that apply.

skad [1K]

7, 3, 2, 0 are in the domain of the function.

5 0

2 years ago

Read 2 more answers

A man is on a diet and goes into a shop to buy some turkey slices. He is given 3 slices which together weigh 1/3 of a pound, but

Gelneren [198K]

In order to compare 1/4 of a pound with 1/3 of a pound, we take them to the same dominator.
1/4=3/12
1/3=4/12

if 3 slices weigh ................... 4/12 of a pound
x slices weigh ................... 3/12 of a pound

x= $\frac{3* \frac{3}{12} }{ \frac{4}{12} } = \frac{ \frac{9}{12} }{ \frac{4}{12} } = \frac{9}{4} = 2.25$

He can actually eat 2 slices and a quarter.

5 0

3 years ago

Read 2 more answers

CL 1-148. The county-fair prize wheel has equally spaced sections with the following colors:

Nina [5.8K]

Answer:

A. $\dfrac{1}{25}=0.04$ or 4%

B. $\dfrac{16}{25}=0.64$ or 64%

C. 8 times

Step-by-step explanation:

The county-fair prize wheel has equally spaced sections with the following colors: 1 is golden, 2 are silver, 3 are green, 4 are blue, 6 are red, and 9 are yellow, 25 sections in total.

A. The probability of landing on gold is

$P_1=\dfrac{\text{Number of favorable outcomes}}{\text{Number of all possible outcomes}}=\dfrac{1}{25}=0.04$