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Anna [14]
3 years ago
11

M - 7 < 6 please help me

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
<span>the answer is M<13 for problems like this you can go to https://www.cymath.com/answer.php?q=solve%20M%20-%207%3C%206 to solve your answer</span>
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Find Sn for the given arithmetic series a1=-26 d=-9 n=24
ryzh [129]

Answer:

- 3108

Step-by-step explanation:

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a_{1} + (n - 1)d ]

Substitute the given values into the formula

S_{24} = \frac{24}{2} [ (2 × - 26) + (23 × - 9) ]

                          = 12 ( - 52 - 207 )

                         = 12 × - 259 = - 3108

5 0
3 years ago
6/x = x-1<br> that 6overx = x-1
Juliette [100K]
6/x = x-1

Multiply x by both sides

6= x(x-1)

Set x and x-1 equal to 6

x = 6, x = 1+6 = 7
6 0
3 years ago
The rate at which a plant grows is constant. At the 3rd week it is 12 inches tall and at the 5th week it is 20 inches tall. If t
Likurg_2 [28]
It would be (12,20) or (20,12) I don't know which one
5 0
3 years ago
Two sides of an acute triangle meaure 5 inches and 8 inches. The length of the longest side is unknown. What is the greatest pos
gladu [14]

The greatest whole possible whole number length of the unknown side is 9 inches.

<h3>How to identify if a triangle is acute?</h3>

Let us have:

H = biggest side of the triangle

And let we get  A and B as rest of the two sides.

Then we get:

If

A^2 + B^2 < C^2

then the triangle is acute

Two sides of an acute triangle measure as 5 inches and 8 inches

The length of the longest side is unknown.

We have to find the length of the unknown side

WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

A^2 + B^2 < C^2

Here in this sum,

a = 5 inches

b = 8 inches

c = ?

Substituting we get,

A^2 + B^2 < C^2\\\\5^2 + 8^2 < C^2\\\\25 + 64= C^2

c < 9

Hence, The greatest whole possible whole number length of the unknown side is 9 inches.

Learn more about angles;

brainly.com/question/14489478

#SPJ1

3 0
2 years ago
You can run 5 miles in 25 minutes. At this rate, how many miles can you run in 3 hours
kotegsom [21]
Well, if you run 5 miles in 25 minute you run a mile every 5 minutes. So, there is 190 minutes in 3 hours. So we would need to divide 190 by 5 which is 38. So, the person could run 38 miles in 3 hours. 
7 0
3 years ago
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