Answer:
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Step-by-step explanation:
f(x) ≥ -(x+4)^2
f(x) ≥ -(x- -4)^2
this is in the form
f(x)> a(x-h)^2 +k
where (h,k) is the vertex and h is the axis of symmetry
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Hello from MrBillDoesMath!
Answer:
-9 sqrt(5)
Discussion:
-2 sqrt(20) - sqrt(125) =
-2 *2 sqrt(5) - sqrt(125)= as 20 = 4* 5
-4sqrt(5)- 5 sqrt(5) = as 125 = 25 *5
(-4 -5) sqrt(5) =
-9 sqrt(5)
Thank you,
MrB
Answer:
the correct answer is Trinomial
Answer:
A
Step-by-step explanation:
Think of a value on the unit circle that is double of 165.
330 is that so we can use the double Angle Identity

Alpha is 330
so




