PLEASE HELP Consider these functions f(x)=x+1

Mathematics

1 answer:

NeTakaya2 years ago

6 0

Answer:

fo(g(X)= 2/X +1.

Option C

Step-by-step explanation:

Hey there!

Given;

f(X) = x+1

g(x) = 2/X

Now, To find: (f o g(x))

$fo(g(x)) = f(g(x))$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = f( \frac{2}{x} )$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2}{x} + 1$

Therefore, fo(g(X)= 2/X +1.

Hope it helps...

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sergij07 [2.7K]

Answer:

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Step-by-step explanation:

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_________

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You start by placing the c in the top left corner, then list all the coefficients of your dividend [x² + x - 17]. You bring down the original term closest to c then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, the 5 follows right behind it, and bringing up the rear, $\displaystyle \frac{3}{x - 4},$ giving you the quotient of $\displaystyle x + 5 + \frac{3}{x - 4}.$ However, in this case, since you have a remainder of 3, this gets set over the divisor.