The answer is already in its simplest form. You can not add the two because the have different variables. Hope this helps ;)))
6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
Answer:
y=1/2x-10
Step-by-step explanation:
y=1/2x+b
-8=1/2(4)+b
-8=2+b
-10=b
y=1/2x-10
Answer:
7.2 is your answer:)
Step-by-step explanation:
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-7%3D1%5Bx-%28-1%29%5D%5Cimplies%20y-7%3Dx%2B1%20%5C%5C%5C%5C%5C%5C%20y%3Dx%2B8%5Cimplies%20%5Cboxed%7B-x%2By%3D8%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7Bx-y%3D-8%7D)
just to point something out, is none of the options, however -x + y = 8, is one, though improper.
