Answer:
(3, 0).
Step-by-step explanation:
dentifying the vertices of the feasible region. Graphing is often a good way to do it, or you can solve the equations pairwise to identify the x- and y-values that are at the limits of the region.
In the attached graph, the solution spaces of the last two constraints are shown in red and blue, and their overlap is shown in purple. Hence the vertices of the feasible region are the vertices of the purple area: (0, 0), (0, 1), (1.5, 1.5), and (3, 0).
The signs of the variables in the contraint function (+ for x, - for y) tell you that to maximize C, you want to make y as small as possible, while making x as large as possible at the same time.
Hence, The Answer is ( 3, 0)
B has more because 10/5 is 2 and 8/12 is less
I have drawn three obtuse angles showing three different positions.
then taken a point p inside it.
Now to draw perpendicular from a point to a given line
we draw a line parallel fom that point to that given line.
After that from that point we draw perpendicular to that line.
Now the question arises which side is closer to point p ,
The answer is if length of perpendicular from p to the line is longer that side is farther from the point p , and if the length of perpendicular is shorter then that that line is nearer to point P.
Answer:
95 cents
Step-by-step explanation:
3.80/4 = 0.95
Answer:
Expand the brackets, and simplify.
(4t - 8/5)-(3-4/3t) = (4t +4/3t) + ( -8/5 - 3) = 5 1/3t - 23/5 = 16/3t - 23/5
5(2t + 1) + (-7t + 28) = 10t + 5 - 7t + 28 = 3t + 33
(-9/2t + 3) + (7/4t + 33) = (-9/2t + 7/4t) + (3 + 33) = -11/4t + 36
3(3t - 4) - (2t + 10) = 9t - 12 - 2t - 10 = 7t - 22
