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maxonik [38]
3 years ago
6

Solve the following absolute value inequality. Express your answer in interval notation:

Mathematics
1 answer:
Masteriza [31]3 years ago
6 0

hope this kinda helps

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9. Kevin Durant scored 33 points in a recent game. Here are the outcomes of each
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Answer:

C

Step-by-step explanation:

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Which expression is equivalent to 36a-12b? <br><br> 3(6a-2b). 6(6a-2b). 3(6a+2b). 6(6a+2b)
Maurinko [17]

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6(6a-2b)

Step-by-step explanation:

4 0
3 years ago
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The table shows the battery life of four different mobile phones:
tekilochka [14]
Answer: Phone C

Using quick mental math, we can do 8% of 10 to get 0.8, which is close to the value of 0.0845*10. Also fairly quick is moving the decimal point over 1 spot to the right and we go from 0.0845 to 0.845 and that rounds to 0.8 when rounding to one decimal place. Recall that 8.45% = (8.45/100) = 0.0845

If you want to compute out the four results with a calculator, then it would look like this:
0.0845*20 = 1.69
0.0845*25 = 2.1125
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0.0845*18 = 1.521
and this shows that no other result (but choice C) is close to 0.8

So that's why the answer is choice C
5 0
3 years ago
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If x = -6, which inequality is true?
Sveta_85 [38]

Answer:

A

Step-by-step explanation:

-5 - 3(-6) > 10

-5 - -18 > 10

-5 + 18 > 10

13 > 10

3 0
2 years ago
Help with this question Asap!! I need all the help I can get!
tankabanditka [31]

Answer:

\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X

Step-by-step explanation:

BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y

\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o

\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X

5 0
3 years ago
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