Answer:
y+1 = -1(x+10)
Step-by-step explanation:
The point slope equation of a line is
y-y1 = m(x-x1) where m is the slope and (x1, y1) is a point on the line
y - -1 = -1 (x --10)
y+1 = -1(x+10)
Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:
<h3>How do we add polynomials?</h3>
We add polynomials combining the like-terms, that is, adding terms with the same exponent.
In this problem, the polynomials are:
Combining the like terms, the addition is given by:
More can be learned about addition of polynomials at brainly.com/question/9438778
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Answer:
10x - 3y = -109 .
Step-by-step explanation:
x^2 + y^2 = 109
Implicit Differentiation:
2x + 2y.y' = 0
y' = -2x/2y = -x/y
So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.
Equation of the tangent:
y - y1 = m(x - x1)
y - 3 = 10/3(x + 10)
y - 3 = 10/3 x + 100/3
3y - 9 = 10x + 100
-109 + 3y = 10x
10x - 3y = -109
Answer:
20 per min
Step-by-step explanation:
