Answer:
The probability of the event of identifying both the defective bulb in the second attempt is
.
Step-by-step explanation:
The number of good light bulbs is 5 and the number of defective bulbs is 2.
It is provided that when a defective bulb is found in the inspection it is disposed.
If a defective bulb is found in the first trial the probability of his event is
.
Now the remaining number of bulbs is 6.
If a defective bulb is found in the second trial the probability of his event is
.
So the probability of identifying both the defective bulb in the second attempt is:
P (Selecting a defective bulb in 1st attempt) × P (Selecting a defective bulb in 2nd attempt) =
Thus, the probability of the event of identifying both the defective bulb in the second attempt is
.
Answer:
B
Step-by-step explanation:
You're correct! The law of sines does not involve any operations, it only has equal signs to show equivalency.
Answer:
2⁹
Step-by-step explanation:
Using the rule of Indices:
aⁿ x aˣ = aⁿ⁺ˣ
Hence: 2²⁺³⁺⁴
= 2⁹
Answer:
The answer is C
Step-by-step explanation:
I took it on usa test prep
Answer: 30× 4 = 120
120÷4 = 30
Step-by-step explanation: