Answer:
but what ingredients do i need to buy?
Step-by-step explanation:
This is another one for my "impossible math question" file. All of the answer choices are wrong. (None applies.)
According to the problem statement, the length you have marked "x" in the diagram is 15 inches. If the side length of one of the pavers is "s", then the Pythagorean theorem tells us
s² + (2s)² = 15²
5s² = 225
s² = 225/5 = 45 . . . . . . the area of one square is 45 in² (not 225 in²)
Then
s = √45 = 3√5 . . . . . . . the length of one side is not 5√3
so the perimeter is
p = 4s = 4·3√5 in = 12√5 in ≈ 26.83 in . . . . not 75 inches.
The area of the 6-block L-shaped path is
total area = 6s² = 6·45 in² = 270 in² . . . . not 450 in²
And the total perimeter is 14 sides, so is
total perimeter = 14s = 14·3√5 in = 42√5 in . . . . not 60√3 in
_____
In cases like this where the answer key is incorrect, you might try asking your teacher show the class how to work the problem.
Answer:
y = x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 1, thus
y = x + c ← is the partial equation
To find c substitute (5, 3) into the partial equation
3 = 5 + c ⇒ c = 3 - 5 = - 2
y = x - 2 ← equation of line
1 and 2 are both rational.
3 and 4 are both not.
bearing in mind that perpendicular lines have negative reciprocal slopes, so
![\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B10em%7D%5Cstackrel%7Bslope%7D%7By%3D%5Cstackrel%7B%5Cdownarrow%20%7D%7B-%5Ccfrac%7B1%7D%7B3%7D%7Dx-1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for a line whose slope is 3 and runs through (1,5)
