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ZanzabumX [31]
3 years ago
13

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

2.00 m and 7.00 m. What is the probability that a randomly selected depth is between 2.25 m and 5.00 m?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

Step-by-step explanation:

Let the random variable <em>X</em> denote the water depths.

As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

P(2.25

                               =\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55

Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

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The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15
Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7       Grade 8

  20                  21

  15                  29

  30                  14

  24                  19

   18           24

   21                 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24

The interquartile range for the grade 7 data is

IQR=Q_3-Q_1=24-18=6

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25

The interquartile range for the grade 8 data is

IQR=Q_3-Q_1=25-19=6

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

D=22.5-20.5=2

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

D=x(IQR)

2=x(6)

\frac{2}{6}=x

\frac{1}{3}=x

Therefore the difference is about 1/3 times the interquartile range of either data set.

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