Answer:
Step-by-step explanation:
I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.
The position equation is
That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.
The first derivative of position is velocity:
v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):
0 = -3.72t + 15 and solve for t:\
-15 = -3.72t so
t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:
s(4.03) = -1.86(4.03)² + 15(4.03) so
s(4.03) = 30.2 meters.
Calculus is amazing. Much easier than most methods to solve problems like this.
Tnemos el sisema de ecuaciones:
Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:
Ahora podemos resolver para y con cualquiera de las dos ecuaciones:
Respuesta: x=-3, y=0
A= 1/360 m•pi r^2
11/2= 1/360 m• pi (3)^2
11/2= 1/360 m• pi • 9
Divide 360 by 9
11/2= 1/40 m pi
Cross multiply
440=2pi m
Divide both sides by 2pi
m= 70.02817 degrees round if necessary
Answer:
Positive to negiative and they counded by 2s for the positive one and 6s for the negative one.
Step-by-step explanation:
the answer is 5.10729613...
