Answer:
x = 12
Step-by-step explanation:
Equation: 0.52(x) + 0.72(4) = 0.57(x + 4)
0.52(x) + 0.72(4) = 0.57(x + 4) Multiply
0.52x + 2.88 = 0.57x + 2.28 Subtract 0.52x from both sides
2.88 = 0.05x + 2.28 Subtract 2.28 from both sides
0.6 = 0.05x Divide all sides by 0.05
x = 12
-Chetan K
Answer:
The depreciation each year is option B. $1500.00
Step-by-step explanation:
Initial value of car = $9600
Salvage value = $600
Salvage value is the final value of product after all the depreciation have been applied on the product.
So, total depreciation on the car =
Also, it is given that the depreciation occurs at a straight line method i.e. same depreciation occurs every year.
Depreciation in 6 years = $9000
Depreciation in 1 year =
Hence, option B. $1500 is the correct answer for the depreciation every year.