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Drupady [299]
3 years ago
6

A flower box in the shape of a right rectangular prism is made of thin metal, shown below. The box has length 90 centimeters (cm

), width 45 cm, and height 45 cm. The box is 85 percent filled with soil. Each bag of soil holds 1 cubic (ft^3), and 1 ft^3 is approximately 28,316 cubic centimeters (cm^3). How many bags of soil are needed to finish filling the flower box?
A. 1 bag

B. 2 bags

C. 6 bags

D. 7 bags

Mathematics
2 answers:
Paul [167]3 years ago
6 0
The volume of the box is
.. V = (90 cm)*(45 cm)*(45 cm) = 182,250 cm³
The empty 15% of the volume is then
.. empty volume = 0.15*182,250 cm³ = 27,337.5 cm³

This will require
.. (empty volume)/(volume / bag) = 27,337.5 cm³ / (28,316 cm³/bag) ≈ 0.97 bag
to fill.

Selection A. 1 bag is appropriate.
disa [49]3 years ago
5 0
First of all let's find the volume of the flower box
90×45×45=182250
85% is already filled with soil
182250×85÷100=154912.5
so we need to find the volume NOT filled with soil
182250-154912.5=27337.5
now we need to find out how many 28'316 cubic centimeter bags of soil fit in 27337.5 cubic centimeters of space
27337.5÷28316=( approximately) 1
so the awnser is A 1 bag
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2 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

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qwelly [4]

Answer:

the rule for rotating 90 degrees clockwise is (x,y) to (y,-x). (3,2) will turn into (2,-3)

Step-by-step explanation:

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