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2 years ago

Please show your work! I have 3 more of these, and I want to be able to do them by myself.

Mathematics

1 answer:

Radda [10]2 years ago

3 0

Answer:

Step-by-step explanation:

We group the number 5:

5(x² + 3x + 2.25)

Now inside the brackets we'll take the square root of the coefficient of the x and the square root of the last number, then remove the square from the x and write it as a sum:

5(x+1.5)²

What's the idea behind this?

Well, remember that when you have something in the form:

(a+b)²

It actually means:

a² + 2ab + b²

In our case a was x, and b was 2.25. For bringing it into the shorter form we have to take the square root of a and b.

Sorry if you don't understand. Tell me if you need help to get the xoncept better.

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Safiya deposited money into a bank account that earned 6.5% simple interest each year. After 312 years, she had earned $36.40 in

leonid [27]

Answer:

$1.80

Step-by-step explanation:

Use formula

$I=P\cdot i\cdot t,$

where I is interest, P is total principal, i is rate of interest per year (as decimal) and t is total time in years.

In your case,

I=$36.45, t=312, i=0.065, then

$36.45=P\cdot 0.065\cdot 312,\\ \\P\approx \$1.80$

6 0

3 years ago

Read 2 more answers

25 points

Andrei [34K]

Answer:

34 + x = 70 ; 36

Step-by-step explanation:

Given that:

Current amount = 34

Final amount = 70

Number of roses planted by the workers today ;

Current amount + number planted today = final amount

Let number planted today = x

34 + x = 70

x = 70 - 34

x = 36

7 0

2 years ago

If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the

denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

$\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)$

Now at head wind → $720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)$

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0

3 years ago

HELP ME PLEASE SOMEBODY

In-s [12.5K]

$\huge\boxed{Solution=B,(3,2)}$

5 0

2 years ago

Which figure can be formed from the net?

beks73 [17]

Answer:

its the figure on the top left, so A

brainliest pls! :D

8 0

3 years ago