A)
s = sweater
j = jeans
Equations:
4s + 2j = 140
2s + 3j = 150
B)
4s + 2j = 140
2s + 3j = 150
Multiply (-2) to the second equation
-2 (2s + 3j = 150)
-4s - 6j = -300
Now you have the equations:
4s + 2j = 140
-4s - 6j = -300
-----------------------------add
-4j = -160
j = 40
4s + 2(40) = 140
4s + 80 = 140
4s = 60
s = 15
The cost for a sweater is $15 and the cost for a jean is $40
We used the elimination method to solve the system of equations.
C)
Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85
Total cost for 1 pair of jeans and 3 sweaters = $85
If she has $225 the
$225 / $85 = 2.64
2 jeans = 2 x 40 = $80
6 sweaters = 6 x $15 = $90
So She can only buy 2 jeans and 6 sweaters
Yes you do! In fact not just I. You move al l three down right after or before you move the units to the right.
D'ou know the area of a circle?
Answer:
20 miles with an error margin of ± 8 miles
Step-by-step explanation:
The margin of error of a result is the range in which an error can vary. To find the margin of error between both distances we have to
28-12 = 16, that is, the variation of the result has a range of 16 miles. So we will look for the midpoint of both distances
(X2-X1)/2+X1=(28-12)/2+12=16/2+12=8+12=20
So from this midpoint the value can vary between 8 points below and 8 points above that would cover the difference of 16 miles that we observed at the beginning
In this way, the correct answer is 20 miles with an error margin of ± 8 miles
Done
