<u>Answer:</u>
1 cm : 10.5 km
<u>Step-by-step explanation:</u>
We are given that two towns are 31.5 km in real and are 3 cm apart on a map and we are to find the scale of the map.
For this, we can use the ratio method.
![\frac { 3 cm } { 1 c m } = \frac { 3 1 . 5 k m } { x }](https://tex.z-dn.net/?f=%20%5Cfrac%20%7B%203%20cm%20%7D%20%7B%201%20c%20m%20%7D%20%3D%20%5Cfrac%20%7B%203%201%20.%205%20k%20m%20%7D%20%7B%20x%20%7D%20)
![x = \frac { 3 1 . 5 \times 1 } { 3 }](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%20%7B%203%201%20.%205%20%5Ctimes%201%20%7D%20%7B%203%20%7D%20)
![x = 1 0 . 5](https://tex.z-dn.net/?f=%20x%20%3D%201%200%20.%205%20)
Therefore, the scale of the map would be 1 cm : 10.5 km.
Answer:
0.471
Step-by-step explanation:
The mnemoic SOH CAH TOA reminds you that ...
... Sin = Opposite/Hypotenuse
... sin(S) = 32/68 ≈ 0.471
Answer: I think it is SAS
Step-by-step explanation:
So,
Since this is independent probability, the probability of the event above occurring is:
![(probability\ of\ heads)(probability\ of\ even\ no.)](https://tex.z-dn.net/?f=%28probability%5C%20of%5C%20heads%29%28probability%5C%20of%5C%20even%5C%20no.%29)
First, the probability of landing on heads.
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
Now, the probability of rolling an even number.
<u />
![\frac{3}{6}\ or\ \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B6%7D%5C%20or%5C%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Plug it into the equation.
![\frac{1}{2} * \frac{1}{2} = \frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D%20)
The correct option is C.