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PtichkaEL [24]
3 years ago
13

Find graphical solution of the inequality 3y+2>0

Mathematics
1 answer:
Margarita [4]3 years ago
3 0
Solve for <span>y</span> .<span><span>y><span>−<span>2/3

Hope this helps.
</span></span></span></span>
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What is the product of 5 and x
andrey2020 [161]
I believe the product is 5x. Hope that helps :)
7 0
3 years ago
Read 2 more answers
Who were the 5 European Powers at 5<br> the beginning of WWI. Select all that<br> Apply
cricket20 [7]
Germany, Italy, Japan (axis powers)
Great Britain, Soviet Union, France (allies)
If you only want 5 take out japan
4 0
3 years ago
A polynomial equation with rational coefficients has the roots:​
Sedbober [7]

Answer: (5 - √1) and (4 + √7)

Step-by-step explanation:

Here we have 4 roots, then this is a polynomial of 4th degree.

We can write it as

a*x⁴ + b*x³ + c*x² + d*x + e = 0

We could rewrite this as the product of two quadratic equations:

(a₁*x² + b₁*x + c₁)*(a₂*x² + b₂*x + c₂) = 0

This will be equal to zero when (a₁*x² + b₁*x + c₁) is equal to zero, and when

(a₂*x² + b₂*x + c₂) is equal to zero.

Then we need to find the roots of these two quadratic equations.

And we know that the roots of a quadratic equation like:

a₁*x² + b₁*x + c₁ are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a} = \frac{-b}{2a}   +-\frac{\sqrt{b^2 - 4ac}}{2a}

Then the general form of the roots is something like:

A +-\sqrt{B}

This means that if one of the roots is:

5 + √1, we must have another root equal to 5 - √1

And if we have one root equal to 4 - √7, then we must have another root equal to 4 + √7

Then the correct options are:

(5 - √1) and (4 + √7)

5 0
3 years ago
6x^2+bx+6=(3x+m)(nx+3) for all values of x what is the value of b?
ss7ja [257]
First, Delete these brackets on the right side:
6x^{2}+bx+6=(3x+m)(nx+3) \\ 6x^{2}+bx+6=3nx^{2}+9x+nmx+3m \\ 6x^{2}+bx+6=3nx^{2}+(9+nm)x+3m
Left side and right side are equal, so each parameters have to be equal. Next to "x^2" you've got parameters "6" and "3n".  So:
3n=6   /:3
n=3

Free terms are "6" and "3m", so:
3m=6  /:3
m=2

Next to "x" you've got  "b" and "9+nm" .  We know, that m=2 and n=3  so:
b= 9+nm
b=9+2*3=9+6
So b=15
7 0
3 years ago
Which is equivalent to (9y2-4x)(9y2+4x) , and what type of special product is it?
Gennadij [26K]

Answer:

81y^4 - 16x^2, difference of squares.

Step-by-step explanation:

So we need to expand the following product:

(9y2-4x)(9y2+4x) = 9y2*9y2 + 4x*9y2 - 4x*9y2 -4x*4x = 81y^4 - 16x^2

And this type of product is the difference of squares.

8 0
3 years ago
Read 2 more answers
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