Which is equivalent to (9y2-4x)(9y2+4x) , and what type of special product is it?

Mathematics

2 answers:

Gennadij [26K]2 years ago

8 0

Answer:

81y^4 - 16x^2, difference of squares.

Step-by-step explanation:

So we need to expand the following product:

(9y2-4x)(9y2+4x) = 9y2*9y2 + 4x*9y2 - 4x*9y2 -4x*4x = 81y^4 - 16x^2

And this type of product is the difference of squares.

dedylja [7]2 years ago

6 0

Answer:

Step-by-step explanation:

The given expression is ( 9y² - 4x) (9y² + 4x)

We will simplify the given expression

(9y² - 4x) (9y² + 4x) = 9y² (9y² + 4x) - 4x (9y² + 4x) [Distributive property]

= 81y⁴ + 36xy² - 36xy² - 16x²

= (81y⁴ - 16x²)

This simplified form is the difference of squares of terms (9y²) and (4x)

You might be interested in

Write an absolute value equation that has 3 and 11 as its solution

worty [1.4K]

Answer:

|(x-3)(x-11)|=0

5 0

2 years ago

How does the graph of the function g(x) = 2x – 4 differ from the graph of f(x) = 2x

Lena [83]

9514 1404 393

Answer:

the y-intercepts differ

Step-by-step explanation:

The x-coefficient is the same for each function, so parallel lines are described. The function g(x) has a y-intercept of -4; f(x) has a y-intercept of 0.

The graphs differ in their intercepts.

<em>Additional comment</em>

g(x) can be considered to be a translation downward of f(x) by 4 units. The same graph of g(x) can be obtained by translating f(x) to the right by 2 units. That is, both the x-intercepts and y-intercepts differ between the two functions.