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Effectus [21]
3 years ago
15

Which is equivalent to (9y2-4x)(9y2+4x) , and what type of special product is it?

Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0

Answer:

81y^4 - 16x^2, difference of squares.

Step-by-step explanation:

So we need to expand the following product:

(9y2-4x)(9y2+4x) = 9y2*9y2 + 4x*9y2 - 4x*9y2 -4x*4x = 81y^4 - 16x^2

And this type of product is the difference of squares.

dedylja [7]3 years ago
6 0

Answer:

Step-by-step explanation:

The given expression is ( 9y² - 4x) (9y² + 4x)

We will simplify the given expression

(9y² - 4x) (9y² + 4x) = 9y² (9y² + 4x) - 4x (9y² + 4x)  [Distributive property]

= 81y⁴ + 36xy² - 36xy² - 16x²

= (81y⁴ - 16x²)

This simplified form is the difference of squares of terms (9y²) and (4x)

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Find the value of y for the following system of equations 5x + 3y = 10 x = y - 6
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Answer:

x = -1 , y = 5

Step-by-step explanation:

Solve the following system:

{5 x + 3 y = 10 | (equation 1)

x = y - 6 | (equation 2)

Express the system in standard form:

{5 x + 3 y = 10 | (equation 1)

x - y = -6 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x + 3 y = 10 | (equation 1)

0 x - (8 y)/5 = -8 | (equation 2)

Multiply equation 2 by -5/8:

{5 x + 3 y = 10 | (equation 1)

0 x+y = 5 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = -5 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by 5:

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Collect results:

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