Which is equivalent to (9y2-4x)(9y2+4x) , and what type of special product is it?
2 answers:
Answer:
81y^4 - 16x^2, difference of squares.
Step-by-step explanation:
So we need to expand the following product:
(9y2-4x)(9y2+4x) = 9y2*9y2 + 4x*9y2 - 4x*9y2 -4x*4x = 81y^4 - 16x^2
And this type of product is the difference of squares.
Answer:
Step-by-step explanation:
The given expression is ( 9y² - 4x) (9y² + 4x)
We will simplify the given expression
(9y² - 4x) (9y² + 4x) = 9y² (9y² + 4x) - 4x (9y² + 4x) [Distributive property]
= 81y⁴ + 36xy² - 36xy² - 16x²
= (81y⁴ - 16x²)
This simplified form is the difference of squares of terms (9y²) and (4x)
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