The 90% confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]
Given,
= 731
= 644
= 0.33
= 0.28
z score for 90% confidence interval = 1.645
Here, the confidence interval formula :
( 
) ± z 
Substituting the values, we get
(0.33 - 0.28) ± 1.645 
= 0.05 ± 1.645 
= 0.05 ± 1.645 
= 0.05 ± 1.645 × 0.0248093914
= 0. 05 ± 0.0408114489
Confidence interval:
- 0.05 - 0.0408114489 = - 0.0908114489 ≈ - 0.0908
- 0.05 + 0.0408114489 = - 0.0091885511 ≈ - 0.0092
The confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]
Learn more about confidence interval here:brainly.com/question/17421912
#SPJ4
Answer: b. The sampling distribution of the proportion of damaged trees is approximately Normal
Step-by-step explanation:
The sample mean is an unbiased estimator of the true (unknown) population mean and The sampling distribution shows how the sample mean will vary among repeated samples. In the case above the samples are selected at random from a normally distributed population, and the number of samples selected (n=100) is a bit large therefore the sampling distribution will be approximately normal.
The mid-point of the numbers 3.8 and 4.1 will be 3.95.
<h3>What is the midpoint of line segment AB?</h3>
Let C be the mid-point of the A and B.
C = (A + B) / 2
The numbers are given below.
3.8 and 4.1
Then the mid-point of the numbers 3.8 and 4.1 will be
C = (3.8 + 4.1) / 2
C = 7.9 / 2
C = 3.95
More about the midpoint of line segment AB link is given below.
brainly.com/question/17410964
#SPJ1
First thing you need to know is the measure of the central angle. It is the same as the measure of the arc it intercepts, which is 100 degrees. The formula now is this for the area of a sector:
which comes out to
. If you multiply the pi in you'll get 223.4 or thereabouts.
