3 years ago

If (x + 2) is a factor of x3 − 6x2 + kx + 10, k =

1 answer:

7 0

Hello:
let : f(x) = <span>x3 − 6x2 + kx + 10
</span><span>If (x + 2) is a factor of x3 − 6x2 + kx + 10 : f(-2) = 0
(-2)^3-6(-2)² +k(-2)+10=0
-8 -24-2k +10 = 0
-2k =8+24-10
-2k = 22
k = -11</span>

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2 years ago

Solve the separable differential equation dtdx=x2+164 and find the particular solution satisfying the initial condition x(0)=9

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