If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
(2, 2)
Points B and C are symmetric (Divided by the y axis) so that means we have to find the mirrored version of A that is divided by thee y axis which is (2, 2)
