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AveGali [126]
3 years ago
13

What is the value of y in the solution to the following system of equations? 5x − 3y = −11 2x − 6y = −14 −1 0 1 2

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
5x - 3y = -11 (×2)
2x - 6y = -14 (x5)

10x - 6y = -22
10x - 30y = -70
---------------------- -
24y = 48
y = 2
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Triangle RST is shown. What is the y-coordinate of the final image of vertex T after the triangle is reflected over the x-axis f
gavmur [86]

Answer:

R¹(-7, -3) ,  S¹(-2, -1),  T¹(-5, 4)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

From the graph, the points are R(-4,5), S(1,3),T(-2,-2)

First, the points are reflected over the x-axis then  transform in to

(x,y)→(x,-y)

R(-4,5)→R¹(-4,-5)

S(1,3)→S¹(1,-3)

T(-2,-2)→T¹(-2,2)

<u><em>Step(ii):-</em></u>

Next, The points are shifted to 3 units left then the transform

(x,y)→ (x -3 ,y)

R¹(-4,-5)→ R¹(-4-3, -5) → R¹(-7, -5)

S¹(1,-3)   →   S¹(1-3, -3) →  S¹(-2, -3)

T¹(-2,2)  →   T¹(-2-3, 2)→ T¹(-5, 2)

<u><em>Step(iii):-</em></u>

Now again the points are shifted to '2' units up then transform to

(x,y) )→ (x  ,y+2)

R¹(-7, -5+2) →  R¹(-7, -3)

 S¹(-2, -3+2) →  S¹(-2, -1)

 T¹(-5, 2+2)  →  T¹(-5, 4)

4 0
3 years ago
At what point on the parabola y = 3x^2 + 2x is the tangent line parallel to the line<br> y = 10x −2?
oksian1 [2.3K]

Answer:

( \frac{4}{3} , 8 )

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 10x - 2 ← is in slope- intercept form

with slope m = 10

Parallel lines have equal slopes

then the tangent to the parabola with a slope of 10 is required.

the slope of the tangent at any point on the parabola is \frac{dy}{dx}

differentiate each term using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1} , then

\frac{dy}{dx} = 6x + 2

equating this to 10 gives

6x + 2 = 10 ( subtract 2 from both sides )

6x = 8 ( divide both sides by 6 )

x = \frac{8}{6} = \frac{4}{3}

substitute this value into the equation of the parabola for corresponding y- coordinate.

y = 3(\frac{4}{3} )² + 2

   = (3 × \frac{16}{9} ) + 2

   = \frac{16}{3} + \frac{8}{3}

   = \frac{24}{3}

   = 8

the point on the parabola with tangent parallel to y = 10x - 2 is ( \frac{4}{3} , 8 )

3 0
2 years ago
9t-3t+4<br> Please help me ty :)
Ierofanga [76]

Answer: 0.6666666667

Step-by-step explanation: Simplifying

9t + -3t = 4

Combine like terms: 9t + -3t = 6t

6t = 4

Solving

6t = 4

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Divide each side by '6'.

t = 0.6666666667

Simplifying

t = 0.6666666667

8 0
3 years ago
Read 2 more answers
The volume of a cylinder is 81 pi in^3 and the height of the cylinder is 1 in. What is the radius of the​ cylinder
ladessa [460]

Answer:

18/20π

Step-by-step explanation:

81π ÷ 1 = 81π

81π ÷2 = 18/20π

You do this because the radius is half of the diameter and you need to get rid of the hight by dividing it from the volume.

7 0
3 years ago
Find the volume of the figure
Nadusha1986 [10]
Just find the base area then multiply it by the height.
so here for the base area we can divide it in 2 parts 6x6 + 2x1
which the total is 38
then multiply 38 by 1, which is the height, so it's 38
8 0
3 years ago
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