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4 years ago

Is the fee for ride tickets proportional to the number of tickets? Explain your reasoning. Number 13

Mathematics

1 answer:

jolli1 [7]4 years ago

5 0

No it is not, the tickets go up by 5 each time, but the fee changes the number that it goes up each time. Does that make sense?

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The number of runs scored by the home team at a baseball game is represented by ( x + 10). The number of runs scored by the visi

Zinaida [17]

Maria participates in a sports activity and runs the following amount__________45m

Cual es la respuesta???????

7 0

3 years ago

Boldface publishing company reported a loss of $17,225 in march. In April, the company showed a profit of $32,500. How much more

Dmitrij [34]

Answer:

Boldface publishing company had $49,725 more in April than March

Step-by-step explanation:

Step 1

Express the total amount of money Boldface had in March as shown;

Let the initial amount of money he had be;

initial=x

loss=$17,225

Net amount=initial amount-loss

Net amount in March=x-17,225

Step 2

Express the total amount of money Boldface had in April as shown;

Let the initial amount of money he had be;

initial=x

profit=$32,500

Net amount=initial amount+profit

Net amount in April=x+32,500

Step 3

To calculate how much more Boldface make in April than March;

Net amount in April-net amount in March

where;

net amount in April=x+32,500

net amount in March=x-17,225

replacing;

(x+32,500)-(x-17,225)

x+32,500-x+17,225

x-x+32,500+17,225=49,725

Boldface publishing company had $49,725 more in April than March

5 0

3 years ago

Amy, Bruce and Carlos collected a total of 168 pounds of cans to recycle. Bruce collected 1/3 the number of pounds of cans Carlo

disa [49]

A + b + c = 168
b = 1/3c
a = b + c....a = 1/3c + c = 4/3c

now we sub
4/3c + 1/3c + c = 168
8/3c = 168
c = 168 * 3/8
c = 504/8
c = 63 <=== Carlos collected 63 lbs

a = 4/3c
a = 4/3(63)
a = 252/3
a = 84 <== Amy collected 84 lbs

b = 1/3c
b = 1/3(63)
b = 63/3 <== Bruce collected 21 lbs
b = 21

3 0

3 years ago

Help with the following problem please

Effectus [21]

Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle = $\pi R^2=\pi7^2=49\pi$
Area of large shaded circle = $\pi x^2=\pi5^2=25\pi$
Area of 4 small shaded circles = $4\pi r^2=4\pi1^2=4\pi$
Total area of shaded circles = $25\pi+4\pi=29\pi$

Shaded area as a fraction of that of the outer circle
$=\frac{29\pi}{49\pi}=29/49$

3 0

3 years ago

Thirty-one thousand, eight hundred eighty-nine

tangare [24]

Answer:

where is the question?

Step-by-step explanation:

7 0

3 years ago