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Irina18 [472]
3 years ago
13

the gravitational attraction between two masses varies inversely as the square of the distance between them. if the attraction f

orce between them is 75lbs when the bodies are eight feet apart, find the attraction when the masses are twelve feet apart
Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

  33 1/3 lb

Step-by-step explanation:

When the distance between them goes from 8 ft to 12 ft, it is 1.5 times what it was. Then the force will be multiplied by the inverse of the square of this:

  (75 lb)×1/(1.5²) = 75/2.25 lb = 33 1/3 lb

At 12 feet apart, the attraction force is 33 1/3 pounds.

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Baseball hat is on sale for 15% off, which is $2.70. How much does the baseball hat cost at full price?
lidiya [134]

Answer:

27.9 dollars

Step-by-step explanation:

2.70= 15 percent

2.70x2=5.4=30 percent

5.4+2.70=8.1=45 percent

8.1x2=16.2=95 percent

95 percent + 15 percent=18.9

18.9=105 percent

in order to subtract 5 percent we need to find 5 percent by dividing 2.70 by 3

which = .9

18.9+9=27.9

100 percent is 27.9 dollars

4 0
3 years ago
Go step by step to reduce the radical.<br> V216
oksano4ka [1.4K]

Answer:

6\sqrt{6}

Step-by-step explanation:

\sqrt{216}

factorise 216

\sqrt{2*2*2*3*3*3}

since it is square root (meaning it has index to) pair up the number

2*3\sqrt{2*3

6\sqrt{6}

6 0
3 years ago
Rita is hiking along a trail that is 15.8 miles long. So far she has hiked along one-tenth of the trail. How far has Rita hiked?
Phantasy [73]
The answer is 1.58 miles
8 0
3 years ago
If you were to graph 1.14, 1.15, and 0.5. what would you count by on your number line?
GREYUIT [131]

If you want to include 0, the overall interval is 115 times 0.01, or 23 times 0.05 or 11.5 times 0.10. The latter might make it harder to plot 1.14, so I'd probably use an interval of 0.05.

Between 6 or 7 and about 25 intervals on a graph's scale are about right. More makes it pretty busy and sometimes difficult to tell which mark is associated with the number. A fewer number is indicated only if there are a fewer number of discrete values that need to be shown to adequately identify the data points.

6 0
3 years ago
You cut a circular hole 1/4 -inch in diameter in a piece of cardboard. With the cardboard 30 inches from your face, the Moon fit
Stolb23 [73]

Answer:

The Moon's diameter is greater than 1,500 miles

Step-by-step explanation:

we know that

1\ mile=63,360\ inches

1,500\ miles=1,500*63,360=95,040,000\ inches

240,000\ miles=240,000*63,360=15,206,400,000\ inches

by proportion

Find the Moon's diameter

Let

x-----> the Moon's diameter in inches

\frac{x}{15,206,400,000}=\frac{0.25}{30}\\ \\x= 15,206,400,000*0.25/30\\ \\x=126,720,000\ inches

Compare

126,720,000\ inches> 95,040,000\ inches

therefore

The Moon's diameter is greater than 1,500 miles

3 0
3 years ago
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