3 years ago

Can someone PLEASE SOLVE ALL OF THESE?!?! PLEASE ITS AN EMERGENCY!!!

Mathematics

1 answer:

ruslelena [56]3 years ago

7 0

3. 11, 87
4. 35, 70, 75
5. Width=9 Length=23
6. 18, 21, 25
7. Bob types 39 WPM.

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43214568•19876555<br><br> Please help me!!!!!!!!

Bess [88]

Answer:

8.5895674e+14

Step-by-step explanation:

Use a calculator.

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3 years ago

Z is the midpoint of XY<br> XY = 27

Nimfa-mama [501]

X=13.5

Y=13.5

Therefore Z is 13.5

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2 years ago

Read this excerpt from A Black Hole is NOT a Hole.

diamong [38]

Answer:

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Step-by-step explanation:

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3 years ago

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Is 1/2x-4 a function?

lakkis [162]

Answer:

Yes it is

Step-by-step explanation:

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3 years ago

Find a polynomial function with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicit

valkas [14]

Given:

Zero: 2, multiplicity: 3

Zero: 0, multiplicity: 2

Degree: 5

Leading coefficient = 1

To find:

The polynomial function.

Solution:

The general form of a polynomial is

$P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}$

where, a is a constant, $c_1,c_2,...,c_n$ are zeroes with multiplicity $m_1,m_2,...,m_n$ .

Using the given information and the general form of a polynomial, we get

$P(x)=a(x-2)^{3}(x-0)^{2}$

$P(x)=ax^2(x^3-6x^2+12x-8)$

$P(x)=a(x^5-6x^4+12x^3-8x^2)$

Leading coefficient is 1, so the value of a is also 1.

$P(x)=1(x^5-6x^4+12x^3-8x^2)$

$P(x)=x^5-6x^4+12x^3-8x^2$

Therefore, the required polynomial is $P(x)=x^5-6x^4+12x^3-8x^2$ .

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3 years ago