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2 years ago

Read this excerpt from A Black Hole is NOT a Hole.

Mathematics

2 answers:

diamong [38]2 years ago

8 0

Answer:

I think the author is meaning to tell you to use your imagination to think about what will happen when you enter. You don’t know until you through it.

Step-by-step explanation:

Yuliya22 [10]2 years ago

3 0

Answer:

Step-by-step explanation:

Sorry if this is wrong its one of those edge quizes that dosnt tell you if you got it right or not.

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What is the remainder when 14,952 is divided by 41? Is the answer, 28, 29 or 30, or 31?

Bas_tet [7]

Answer:

Step-by-step explanation:

49*364= 14924

14952 - 14924= 28

5 0

3 years ago

What is the answer to 4t−t+2

Alexeev081 [22]

Answer:

3t+2

Step-by-step explanation:

First, we focus on the part with the "t" variable. Then we subtract the values with variables which gets us 3t. Finally, we can't do anything with the +2, so our solution is 3t+2.

6 0

2 years ago

3. The student council bought t-shirts from a company for $9 apiece. They also spent a

MAVERICK [17]

Im pretty sure its 7770

7 0

3 years ago

Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)

fredd [130]

Answer:

$f(x)=\frac9{x+1}\\ f'(x)=-\frac9{(x+1)^2}\\ f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\\ |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\\ x_1=2\ \vee\ x_2=-4\\ f(x_1)=f(2)=\frac9{2+1}=3\\ f(x_2)=f(-4)=\frac9{-4+1}=-3$

First tangent line:

$y=f'(x_1)\cdot (x-x_1)+f(x_1)\ \to \ y=-1(x-2)+3\ \to \ y=-x+5$

Second tangent line:

$y=f'(x_2)\cdot (x-x_2)+f(x_2)\ \to \ y=-1(x+4)-3\ \to \ y=-x-7$

Notice: slope of -1 means that both $f'(x_1), \ f'(x_2)$ are equal to -1, so $f'(x_1)=-1 \ and \ f'(x_2)=-1$

6 0

2 years ago

Read 2 more answers

PLEASE HELP!!<br> Convert each linear equation to standard form.<br> y-4= -2(x+3)

hjlf

So first, this is point slope form. The first step is to distribute.)
$y-4=-2x-6$
Then add 4 to both sides.
$y=-2x-2$
Then add 2x and it becomes
$2x+y=-2$

4 0

3 years ago

Read 2 more answers