(5,7) because when you divide that’s the answer you get
Answer:
14
Divide
12 and 1 over 412
1
4
÷ 7 over 8
7
8
= 392 over 28
392
28
Step 1 of 2: Divide, sub-step a: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
12 and 1 over 412
1
4
= ( 12 × 4 ) over 4
12 × 4
4
+ 1 over 4
1
4
= ( 48 + 1 ) over 4
48 + 1
4
= 49 over 4
49
4
Step 1 of 2: Divide, sub-step b: Divide.
Divide
49 over 4
49
4
÷ 7 over 8
7
8
= 49 over 4
49
4
× 8 over 7
8
7
= ( 49 × 8 ) over ( 4 × 7 )
49 × 8
4 × 7
= 392 over 28
392
28
To divide fractions, invert the second one (turn it upside-down), then multiply the numerators and denominators.Divide
12 and 1 over 412
1
4
÷ 7 over 8
7
8
= 392 over 28
392
28
Step 1 of 2: Divide, sub-step a: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
12 and 1 over 412
1
4
= ( 12 × 4 ) over 4
12 × 4
4
+ 1 over 4
1
4
= ( 48 + 1 ) over 4
48 + 1
4
= 49 over 4
49
4
Step 1 of 2: Divide, sub-step b: Divide.
Divide
49 over 4
49
4
÷ 7 over 8
7
8
= 49 over 4
49
4
× 8 over 7
8
7
= ( 49 × 8 ) over ( 4 × 7 )
49 × 8
4 × 7
= 392 over 28
392
28
To divide fractions, invert the second one (turn it upside-down), then multiply the numerators and denominators.
Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
a² + b² = 68
a3 + b3 = 520
Step-by-step explanation:
Given :
a + b = 10 (1)
ab = 16 (2)
A. Find a² + b²
(a + b)² = a² + 2ab + b² (3)
Substitutite the values of (1) and (2) into (3)
(10)² = a² + 2(16) + b²
100 = a² + 32 + b²
Subtract 32 from both sides
100 - 32 = a² + b²
a² + b² = 68
B. a^3 + b^3
(a + b)^3 = a^3 + b^3 + 3ab(a + b)
(10)^3 = a^3 + b^3 + 3*16(10)
1000 = a^3 + b^3 + 480
a^3 + b^3 = 1000 - 480
a3 + b3 = 520
