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klemol [59]
3 years ago
13

The sale is for $30 this is 75 % of the original price find the original price

Mathematics
1 answer:
Sauron [17]3 years ago
6 0
1. $52.80

2. 80

3. 46 people

4. 15 minutes

5. 2%

6. 147.03

I think these answers are correct but I am not 100% sure
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What is the common denominator for 1 2/3 and 3/4
Elena L [17]

Answer:

The answer is 12

Step-by-step explanation:

Multiply 1*3

Add 2 to the number

Change the first number to 5/3

Multiply 3*4

3 0
2 years ago
Help me with my math quiz from friday 4/1 <br> SHOW STEPS
malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

_______________________________________

4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

\rightarrow\sf{7x - 4=87}

\rightarrow\sf{7x =87+4}

\rightarrow\sf{7x =91}

\rightarrow\sf{x =\frac{91}{7}}

\rightarrow\boxed{\bf{x =13}}

_______________________________________

5. radius = 17ft

circumference of circle = 2πr

\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}

\rightarrow\boxed{\bf{circumference=106.8ft}}

_______________________________________

3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

_______________________________________

2. 160° + (6x - 16)° = 180° (linear pair)

\rightarrow\sf{6x - 16 = 180-160}

\rightarrow\sf{6x - 16 = 20}

\rightarrow\sf{6x = 20+16}

\rightarrow\sf{6x =36}

\rightarrow\sf{x =\frac{36}{6}}

\rightarrow\boxed{\bf{x =6}}

8 0
2 years ago
How do i put this in least to greathest 0.5 -1 ,2/3, 1.1
victus00 [196]
-1, 0.5, 2/3, 1.1 is the order of the numbers from least to greatest
6 0
3 years ago
Will mark Brainlist!
butalik [34]

Answer:

4,880

Step-by-step explanation:

33.2% x 14,700 = 4880 employes

8 0
3 years ago
Read 2 more answers
1. Approximate the given quantity using a Taylor polynomial with n3.
Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

f(x) = x^{1/4}

The n-th order Taylor polynomial for function f with its center at a is:

p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}

As n = 3  So,

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}

p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} }  (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} +  (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}

p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} }  (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} +  (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}

p_{3} (x) = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6  

                                                                                  (0.0000018522752) (x-81)³

p_{3} (x)  =  0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

                                                                                                       (x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

p_{3} (94)  =  0.0092592593 (94) - 0.000042866941 (94 - 81)² +          

                                                                 0.00000030871254 (94-81)³ + 2.25

         = 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +    

                                                                                                                       2.25

         = 0.87037 03742 - 0.000042866941 (169) +  

                                                                      0.00000030871254(2197) + 2.25

         = 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

p_{3} (94)  = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute \sqrt[4]{94} as 94^{1/4} using calculator

Exact value:

E_{a}(94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94)  = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94)  = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94)  = 0.0001

4 0
3 years ago
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