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Lyrx [107]
3 years ago
8

I need to find what x is equal to

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
4 0

Answer:

f(x)= -7 -7 +3+5+17

= -14+25

= 11

You might be interested in
What is the area of a triangle that has a base of 15 yards and a height of 11 yards?
erma4kov [3.2K]

Answer:

82.5

Step-by-step explanation:

The formula for the area of triangle is 1/2 B * H

1/2 of the base is 7.5

multiply that by 11

and you get

82.5

4 0
4 years ago
The table shows how much each fift grade room earned from a bake sale.The money is going to be given to 6 charities.If each Char
finlep [7]
I can't see the table, but you find the total amount that the entire fifth grade made and divide it by six. I would round it to the nearest hundredth.
6 0
4 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
2^x + 2^-x =5/2 pls I need d. ans​
yKpoI14uk [10]

Answer:

x= 1, -1

Step-by-step explanation:

6 0
3 years ago
Pls help urgent
tangare [24]
It's just asking for the gradient basically
150/3 = 50
Or technically -50 because it's decreasing
7 0
3 years ago
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